Q. 48
A chemist has one solution containing 50% acid and a second one containing 25% acid. How much of each should be used to make 10 litres of a 40% acid solution?
Answer :
Let the 50% solution used be x litres
Total volume of solution = 10 litres ( Given )
∴ 25% solution used = (10 - x) litres
Volume of acid in mixture = 40% of 10 litres = 4 litres
but, volume of acid in mixture = 50% of x + 25% of (10 - x)
⇒ x + 10 = 16
⇒ x = 6 litres
Thus, 50% solution = 6 litres and 25% solution = 4 litres.
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