Q. 48

# A chemist has one solution containing 50% acid and a second one containing 25% acid. How much of each should be used to make 10 litres of a 40% acid solution?

Let the 50% solution used be x litres

Total volume of solution = 10 litres ( Given )

25% solution used = (10 - x) litres

Volume of acid in mixture = 40% of 10 litres = 4 litres

but, volume of acid in mixture = 50% of x + 25% of (10 - x)

x + 10 = 16

x = 6 litres

Thus, 50% solution = 6 litres and 25% solution = 4 litres.

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