Q. 453.6( 16 Votes )
The present age of a woman is 3 years more than three times the age of her daughter. Three years hence, the woman's age will be 10 years more than twice the age of her daughter. Find their present ages.
Let the age of woman and her daughter be x and y years respectively.
According to Question -
x = 3y + 3.....(1)
x + 3 = 10 + 2(y + 3)
⇒ x - 2y = 13.....(2)
Substitute equation (1) into equation (2), we get -
y = 10
Substituting the value of y in equation (2), we get
x = 33
Thus, the age of woman = 33 years
and, the age of her daughter = 10 years.
Rate this question :
Solve the following pair of linear equation by cross - multiplication method:
x + 4y + 9 = 0
5x – 1 = 3yKC Sinha - Mathematics