Q. 423.9( 25 Votes )
Five years hence, a man's age will be three times the age of his son. Five years ago, the man was seven times as old as his son. Find their present ages.
Answer :
Let the age of the man and his son be x and y years respectively.
According to question -
Five years hence, a man's age will be three times the age of his sonx + 5 = 3(y + 5)
⇒ x - 3y = 10.....(1)
and,
Five years ago, the man was seven times as old as his sonx - 5 = 7(y - 5)
⇒ x - 7y = - 30.....(2)
Subtracting Equation (2) from (1), we get -
⇒ -3y + 7y = 10 + 30⇒ 4y = 40
⇒ y = 10
Substituting the value of y in equation (1), we get -
⇒ x - 3(10) = 10⇒ x = 30 + 10
⇒ x = 40
Thus, Man's age, x = 40 years
and son's age, y = 10 years
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