Answer :

Let the basic first class full fare and reservation charge be Rs. x and Rs. y respectively.


According to question -


Full fare + reservation charge = Rs. 4150


x + y = 4150.....(1)


and,


[full fare + reservation charge] + [half fare + reservation charge] = Rs. 6255


x + y + (x/2) + y = 6255


(3x/2) + 2y = 6255.....(2)


Subtracting equation (2) from [2×equation (1)], we get -


x/2 = 2045


x = 4090


Substituting the value of x in the equation (1), we get -


y = 60


Thus, basic full fare = Rs. 4090


reservation charge = Rs. 60


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