# A railway half ti

Let the basic first class full fare and reservation charge be Rs. x and Rs. y respectively.

According to question -

Full fare + reservation charge = Rs. 4150

x + y = 4150.....(1)

and,

[full fare + reservation charge] + [half fare + reservation charge] = Rs. 6255

x + y + (x/2) + y = 6255

(3x/2) + 2y = 6255.....(2)

Subtracting equation (2) from [2×equation (1)], we get -

x/2 = 2045

x = 4090

Substituting the value of x in the equation (1), we get -

y = 60

Thus, basic full fare = Rs. 4090

reservation charge = Rs. 60

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