# A train covered a certain distance at a uniform speed. If the train had been 5 kmph faster, it would have taken 3 hours less than the scheduled time. And, if the train were slower by 4 kmph, it would have taken 3 hours more than the scheduled time. Find the length of the journey.

Let the speed of train be s kmph and the scheduled time be t hours

Also, Let the length of journey be d.

s × t = d.....(1)

According to question -

(s + 5)(t - 3) = d

st - 3s + 5t - 15 = d

3s - 5t = - 15.....(2) [ s × t = d from (1) ]

and,

(s - 4)(t + 3) = d

st + 3s - 4t - 12 = d

3s - 4t = 12.....(3) [ s × t = d from (1) ]

Subtracting equation (2) from (3), we get -

t = 27

Substituting the value of t in equation (3), we get -

s = 40

d = s × t = 40×27 = 1080 km

Thus, the length of the journey = 1080 Km

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