# Solve for x and y:4x - 3y = 8, We have,

4x – 3y = 8 …eq.1 …eq.2

Let us first simplify eq.2 by taking LCM of denominator,

Eq.2 18x – 3y = 29 …eq.3

To solve these equations, we need to make one of the variables (in both the equations) have same coefficient.

And it is so that the equations 1 & 3 have variable y having same coefficient already, so we need not multiply or divide it with any number.

Recalling equations 1 & 3,

4x – 3y = 8

18x – 3y = 29

4x – 3y = 8

18x – 3y = 29

On solving the above equations we get,

- 14x = - 21  Substitute in eq.1/eq.3, as per convenience of solving.

Thus, substituting in eq.1, we get

4 – 3y = 8

6 – 3y = 8

3y = 6 – 8

3y = - 2 Hence, we have and Rate this question :

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