Answer :

We have,

b2x + a2y = a3b + ab3 …(i)

x + y = 2ab …(ii)

To solve these equations, we need to make one of the variables (in both the equations) have same coefficient.

Lets multiply equation (ii) by a2, so that variable y in both the equations have same coefficient.

Recalling equations (i) & (ii),

b2x + a2y = a3b + ab3

x + y = 2ab [×a2]

b2x – a2x = - a3b + ab3

(b2 – a2)x = ab(b2 – a2)

x = ab

Substitute x = ab in equations (i)/(ii), as per convenience of solving.

Thus, substituting in equation (ii), we get

(ab) + y = 2ab

y = ab

Hence, we have x = ab and y = ab.

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