# Solve for x and y:2x + 3y = 0, 3x + 4y = 5.

We have,

2x + 3y = 0 …eq.1

3x + 4y = 5 …eq.2

To solve these equations, we need to make one of the variables (in both the equations) have same coefficient.

Lets, multiply eq.1 by 3 and eq.2 by 2, so that variable x in both the equations have same coefficient.

Recalling equations 1 & 2,

2x + 3y = 0 [×3

3x + 4y = 5 [×2

6x + 9y = 0

6x + 8y = 10

On solving the two equations we get,

y = - 10

Substitute y = - 10 in eq.1/eq.2, as per convenience of solving.

Thus, substituting in eq.1, we get

2x + 3( - 10) = 0

2x = 30

x = 15

Hence, we have x = 15 and y = - 10.

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