# Solve for x and y:2x + 3y + 1 = 0, After rearrangement, we have

2x + 3y = - 1 …eq.1 …eq.2

Let us first simplify eq.2 by taking LCM of denominator,

Eq.1 7 – 4x = 3y

4x + 3y = 7 …eq.3

To solve these equations, we need to make one of the variables (in both the equations) have same coefficient.

And it is so that the equations 1 & 3 have variable y having same coefficient already, so we need not multiply or divide it with any number.

Recalling equations 1 & 3,

2x + 3y = - 1

4x + 3y = 7

On solving these two equations we get,

x = 4

Substitute x = 4 in eq.1/eq.3, as per convenience of solving.

Thus, substituting in eq.3, we get

4(4) + 3y = 7

16 + 3y = 7

3y = 7 – 16

3y = - 9

y = - 3

Hence, we have x = 4 and y = - 3

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