Answer :

(i) Given: A = {-1, 0, 1, 2} and B = {2, 3, 4, 5}

Function:


(i) all elements of the first set are associated with the elements of the second set.


(ii) An element of the first set has a unique image in the second set.


f = {(–1, 2), (-1, 3), (0, 4), (1, 5)}




Here, -1 is coming twice.


Hence, it does not have a unique (one) image.


f is not a function


(ii) Given: A = {-1, 0, 1, 2} and B = {2, 3, 4, 5}


Function:


(i) all elements of first set is associated with the elements of second set.


(ii) An element of first set has a unique image in second set.


g = {(0, 2), (1, 3), (2, 4)}



Here, -1 is not associated with any element of set B


Hence, it does not satisfy the condition of the function


g is not a function.


(iii) Given: A = {-1, 0, 1, 2} and B = {2, 3, 4, 5}


Function:


(i) all elements of first set is associated with the elements of second set.


(ii) An element of first set has a unique image in second set.


h = {(-1, 2), (0, 3), (1, 4), (2, 5)}



Here, (i) all elements of set A are associated to element in set B.


(ii) an element of set A is associated to a unique element in set B.


h is a function.


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