Q. 135.0( 4 Votes )

# Solve each of the following given systems of equations graphically and find the vertices and area of the triangle formed by these lines and the x - axis:4x – 3y + 4 = 0, 4x + 3y – 20 = 0

We can rewrite the equations as:

4x – 3y = - 4

& 4x + 3y = 20

For equation, 4x – 3y = - 4

First, take x = 0 and find the value of y.

Then, take y = 0 and find the value of x.

Now similarly solve for equation, 4x + 3y = 20

Plot the values in a graph and find the intersecting point for the solution.

Hence, the solution so obtained from the graph is (2,4), which is the intersecting point of the two lines.

The vertices of the formed triangle ABC by these lines and the x - axis in the graph are A(2,4), B( - 1,0) and C(5,0).

Clearly, from the graph we can identify base and height of the triangle.

Now, we know

Area of Triangle = 1/2 × base × height

Thus, Area(∆ABC) =

[ Base = BO + OC = 1 + 5 = 6 units & height = 4 units]

Area(∆ABC) = 12 sq. units

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Dealing With the Real Life Problems53 mins
Quiz | Solution of Linear Equations53 mins
Champ Quiz | Consistency and Inconsistency of Solutions36 mins
Pair of Linear Equations in Two Variables46 mins
Smart Revision | Important Word Problems37 mins
Dealing with the Real Life Problems54 mins
Quiz | Real Life Problems Through Linear Equations56 mins
Elimination (quicker than quickest)44 mins
Bonus on Applications of Linear Equations in Two Variables43 mins
NCERT I Quiz on Solution of Linear Equations in Two Variables49 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses