Answer :

Given: Father’s age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children.

To find: the age of father.

Solution:

Let the present age of father be ‘a’ and present sum of age of both sons be b.

Given, Father’s age is three times the sum of ages of his two children. 

a = 3b

After 5 years his age will be twice the sum of ages of two children.

So age of father will be a + 5 and as there are two sons, age of both sons combined after 5 years will be b + 10. 

⇒ a + 5 = 2(b + 10) 

Put the value of a in above equation,

3b + 5 = 2b + 20

3b - 2b = 20 - 15

b = 15

Thus, a = 3b = 3 (15) = 45

Hence father's present age is 45 years.

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