# Five years ago, N

Given: Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as old as Sonu.
To find: The age of Nuri and Sonu.
Solution:
Let the present age of Nuri and his son be ‘a’ and ‘b’ respectively.

Given, Five years ago, Nuri was thrice as old as Sonu.

This implies age of Nuri and Sonu five years ago was a - 5 and b - 5.

⇒ a – 5 = 3(b – 5)

⇒ a - 5 = 3b – 15
⇒ a = 3b – 15 + 5

⇒ a = 3b – 10 ------- (1)

Ten years later, Nuri will be twice as old as Sonu.
This implies after ten years the age of Nuri and Sonu will be a + 10 and b + 10.

⇒  a + 10 = 2(b + 10)

⇒ a + 10 = 2b + 20
⇒ a = 2b + 20 - 10

⇒ a = 2b + 10 -------- (2)

Equating (1) and (2), we get

3b – 10 = 2b + 10

⇒ 3b - 2b = 10 + 10
⇒ b = 20

Thus, a = 60 – 10 = 50
Hence Nuri's present age is 50 years and Sonu's age is 20 years.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Introduction to Linear Equations in Two Variables62 mins  Revision on Word Problems - 150 mins  Revision on Word Problems - 235 mins  Revision on Substitution and Elimination Method44 mins  Pair of Linear Equations-Yahaan se laye marks57 mins  Resistors in Series33 mins  Steps in Reproduction43 mins  Magnetic Field of Circular Conductor41 mins  Magnetic Effects of Electric Current44 mins  Resistors in Parallel36 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Solve each of theRS Aggarwal - Mathematics

If 2x – 3y = 7 anRD Sharma - Mathematics

Solve the followiRD Sharma - Mathematics