Q. 83.8( 71 Votes )
Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.
To find the required number we have to calculate LCM of 6, 15 and 18 because LCM is the least number divided by all 6, 15 and 18
LCM = 2 × 3 × 3 × 5 = 90
Since the number required always leaves remainder 5
Required number = 90+5 = 95
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