Q. 83.8( 71 Votes )

Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

Answer :

To find the required number we have to calculate LCM of 6, 15 and 18 because LCM is the least number divided by all 6, 15 and 18



LCM = 2 × 3 × 3 × 5 = 90

Since the number required always leaves remainder 5


Required number = 90+5 = 95

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