Q. 44.3( 95 Votes )

Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12.

Answer :

Smallest 3-digit number = LCM of 6, 8 and 12



LCM = 2 × 2 × 2 × 3 = 24


LCM of these 3 numbers is 24 so to find out 3-digit number we have to calculate the multiples of 24,


24 × 1 = 24


24 × 2 = 48


24 × 3 = 72


24 × 4 = 96


24 × 5 = 120


24 × 6 = 144


It can be seen that, 120 is the smallest 3-digit multiple of 24 so, the smallest 3-digit number which is exactly divisible by 6, 8 and 12 is 120.

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