Answer :
Length of the rectangular field = 20m
Breadth of the rectangular field = 14m
Let x be the uniform width all around the path.
Length of the rectangular field including the path
= 20 + x + x
= 20 + 2x
Width of the rectangular field including path
= 14 + x + x
= 14 + 2x
Area of path = area of rectangular field including path – area of rectangular field
⇒ 111 = (20 + 2x)(14 + 2x) – (20 × 14)
⇒ 111 = 280 + 40x + 28x + 4x2 – 280
⇒ 111 = 68x + 4x2
⇒ 4x2 + 68x – 111 = 0
⇒ 4x2 + 74x – 6x – 111 = 0
⇒ 2x(2x + 37) – 3(2x + 37) = 0
⇒ (2x + 37)(2x – 3) = 0
2x + 37 = 0 or 2x – 3 = 0
2x = –37 or 2x = 3
x = –18.5 or x = 1.5
Therefore, width of the path = 1.5m
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