Answer :

According to the question,


x3 – 3x2 + 4x – 12,then put x = 3


then,27 – 27 + 12 – 12 = 0


Then the equation is divisible by x – 3, using division algorithm method.


(x – 3)(x2 + 4) = (x – 3)(x2 + 4)


In equation second,


x4 + x3 + 4x2 + 4x,put x = – 1


then, 1 – 1 + 4 – 4 = 0,


Then the equation is divisible by x + 1, using division algorithm method.


(x + 1)(x3 + 4x) = x(x + 1)(x2 + 4)


Greatest common divisor = (x2 + 4)


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