Answer :

Let the number of pens be ‘a’ and number of pencils be ‘b’.


Given, Reena has pens and pencils which together are 40 in number. If she has 5 more pencils and 5 less pens, then number of pencils would become 4 times the number of pens.


⇒ a + b = 40 ------ (1)


Also, b + 5 = 4(a – 5)


⇒ b = 4a – 25 ------- (2)


Subtracting eq2 from eq1


⇒ a + b – b = 40 – 4a + 25


⇒ 5a = 65


⇒ a = 13


Substituting the value of 'a' in equation (1), we get
⇒ 13 + b = 40
⇒  b = 27
Hence, Reena has 13 pens and 27 pencils.

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