Answer :

Let u(x) = 2x^{2} – 8

On factorizing the above equation,

u(x) = 2(x^{2} – 4)

Let v(x) = x^{2} – 5x + 6

On factorizing the above equation,

Sum = -5

Product = 6

Therefore the two numbers satisfying the above conditions are -2 and -3.

v(x) = x^{2} – 3x – 2x + 6

v(x) = x(x – 3) - 2(x – 3)

v(x) = (x – 2) (x – 3)

By comparing u(x) and v(x),

LCM = 2(x^{2} – 4) (x – 3)

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