Q. 4 B

Expanding the fol

Answer :

Using identity:

(x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2zx


(2 + x + (– 2y))2


= (2)2 + (x)2 + (– 2y)2 + 2(2)(x) + 2(x)(– 2y) + 2(– 2y)(2)


= 4 + x2 + 4y2 + 4x – 4xy – 8y


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