Q. 4 A5.0( 2 Votes )

Expanding the fol

Answer :

Using identity:

(x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2zx


(2a + (– 3b) + (– c))2 = (2a)2 + (– 3b)2 + (– c)2 + 2(2a)(– 3b) + 2(– 3b)(– c) + 2(– c)(2a)


= 4a2 + 9b2 + c2 – 12ab + 6bc – 4ac


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