Q. 2 E5.0( 1 Vote )

Find that value o

Answer :

When we compare the above quadratic equation with the generalized one we get,

ax2 + bx + c = 0


a = k + 4


b = k + 1


c = 1


Since the quadratic equations have real and equal roots,


b2 – 4ac = 0 for real and equal roots


(k + 1) 2 – (4 × (k + 4) × 1) = 0


k2 + 2k + 1 – 4k - 16 = 0


k2 - 2k – 15 = 0


k2 - 2k – 15 = 0


On factorizing the above equation,


Sum = -2


Product = -15


Therefore the two numbers satisfying the above conditions are 3 and -5.


k2 – 5k + 3k – 15 = 0


k(k – 5) + 3(k – 5) = 0


(k + 3) (k – 5) = 0


Solving first part,


k + 3 = 0


k = -3


Solving second part,


k – 5 = 0


k = 5


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

If u(x) = (x – 1)Rajasthan Board Mathematics

Find the lowest cRajasthan Board Mathematics

Solve the followiRajasthan Board Mathematics

Solve the followiRajasthan Board Mathematics

The area of a recRajasthan Board Mathematics

The LCM and HCF oRajasthan Board Mathematics

If α and β are thRajasthan Board Mathematics

Find the zeroes oRajasthan Board Mathematics

Write ShridharachRajasthan Board Mathematics

Solve the followiRajasthan Board Mathematics