Q. 2 B3.7( 3 Votes )

# Find that value o

Answer :

Let us first solve the above equation,

x2 – 2kx + 1x + k2 = 0

When we compare the above quadratic equation with the generalized one we get,

ax2 + bx + c = 0

a = 1

b = -2(k+1)

c = k2

Since the quadratic equations have real and equal roots,

b2 – 4ac = 0 for real and equal roots

(-2(k+1)) 2 – (4 × k2 × 1) = 0

4(k2 + 2k + 1) – 4 k2 = 0

4k2 + 8k + 4 – 4 k2 = 0

8k + 4 = 0

8k = - 4

k = - 4/8

k = - 1/2

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