Answer :

Let fixed hostel charge (monthly) = Rs x

and cost of food for one day = Rs y


In case of student A,


x + 22y = 1380 …(i)


In case of student B,


x + 28y = 1680 …(ii)


On subtracting Eq. (i) from Eq. (ii), we get


x + 28y – x – 22y = 1680 – 1380


6y = 300


y = 50


On putting the value of y = 50 in Eq. (i), we get


x + 22(50) = 1380


x + 1100 = 1380


x = 1380 – 1100 = 280


Hence, monthly fixed charges is Rs. 280 and cost of food per day is Rs. 50


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