Q. 35.0( 1 Vote )

# Find the value of

Answer :

x3 – 6x2 + mx + 60 divided by (x + 2) and remainder = 2

Remainder theorem states that if p(x) is any polynomial and a is any real number and If p(x) is divided by the linear polynomial (x – a) , then the remainder is p(a).

Let p(x) = x3 – 6x2 + mx + 60 and we have (x + 2)

The zero of (x + 2) is –2

Now using Remainder theorem,

p(x) = x3 – 6x2 + mx + 60 is divided by x + 2 then, p(–2) is the remainder which is 2

p(–2) = x3 – 6x2 + mx + 60 = 2

= (–2)3 – 6(–2)2 + m(–2) + 60 =2

= – 8 – 24 – 2m + 60 = 2

= – 32 – 2m + 60 = 2

= 28 – 2m = 2

= 2m = 28 – 2

= 2m = 26

m = 13

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Find the remaindeTamilnadu Board Math Term-I

If (x – 1) divideTamilnadu Board Math Term-I

Find the remaindeTamilnadu Board Math Term-I

Find the remaindeTamilnadu Board Math Term-I

If the polynomialTamilnadu Board Math Term-I

Find the value ofTamilnadu Board Math Term-I

Find the remaindeTamilnadu Board Math Term-I

Find the remaindeTamilnadu Board Math Term-I

When the polynomiTamilnadu Board Math Term-I

Find the remaindeTamilnadu Board Math Term-I