Q. 2 F4.1( 11 Votes )

Find the root of

Answer :

Let us solve the above equation by equating it to zero,




-2 = 3(x2 – 2x)


3x2 – 6x + 2 = 0


When we compare the above quadratic equation with the generalized one we get,


ax2 + bx + c = 0


a = 3


b = -6


c = 2


There is one formula developed by Shridharacharya to determine the roots of a quadratic equation which is as follows:



Before putting the values in the formula let us check the nature of roots by b2 – 4ac >0


(-6)2 – (4 × 3 × 2)


36 – 24


12


Since b2 – 4ac = 5 the roots are real and distinct.


Now let us put the values in the above formula








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