Q. 2 D4.2( 5 Votes )

Find the root of

Answer :

When we compare the above quadratic equation with the generalized one we get,

ax2 + bx + c = 0


a = √2


b = 7


c = 5√2


There is one formula developed by Shridharacharya to determine the roots of a quadratic equation which is as follows:



Before putting the values in the formula let us check the nature of roots by b2 – 4ac >0


(7)2 – (4 × √2 × 5√2)


49 – (20 × 2)


49 – 40


9


Since b2 – 4ac = 121 the roots are real and distinct.


Now let us put the values in the above formula






Solving with positive value first,







x = -√2


Solving with negative value second,





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