Answer :
Let us solve the above equation by equating it to zero,
x2 + 1 = 3x
x2 – 3x + 1 = 0
When we compare the above quadratic equation with the generalized one we get,
ax2 + bx + c = 0
a = 1
b = -3
c = 1
There is one formula developed by Shridharacharya to determine the roots of a quadratic equation which is as follows:
Before putting the values in the formula let us check the nature of roots by b2 – 4ac >0
⟹ (-3)2 – (4 × 1 × 1)
⟹ 9 – 4
⟹ 5
Since b2 – 4ac = 5 the roots are real and distinct.
Now let us put the values in the above formula
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