Q. 2 A3.9( 8 Votes )

Find the root of

Answer :

When we compare the above quadratic equation with the generalized one we get,

ax2 + bx + c = 0


a = 2


b = -2√2


c = 1


There is one formula developed by Shridharacharya to determine the roots of a quadratic equation which is as follows:



Before putting the values in the formula let us check the nature of roots by b2 – 4ac >0


(-2√2)2 – (4 × 2 × 1)


(4 × 2) - 8


8 – 8


0


Since b2 – 4ac = 0 the roots are real and equal.


Now let us put the values in the above formula






x = 1/√2 , 1/√2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

If u(x) = (x – 1)Rajasthan Board Mathematics

Find the lowest cRajasthan Board Mathematics

Solve the followiRajasthan Board Mathematics

Solve the followiRajasthan Board Mathematics

The area of a recRajasthan Board Mathematics

The LCM and HCF oRajasthan Board Mathematics

If α and β are thRajasthan Board Mathematics

Find the zeroes oRajasthan Board Mathematics

Write ShridharachRajasthan Board Mathematics

Solve the followiRajasthan Board Mathematics