Answer :

When we compare the above quadratic equation with the generalized one we get,

ax^{2} + bx + c = 0

a = 2

b = -2√2

c = 1

There is one formula developed by Shridharacharya to determine the roots of a quadratic equation which is as follows:

Before putting the values in the formula let us check the nature of roots by b^{2} – 4ac >0

⟹ (-2√2)^{2} – (4 × 2 × 1)

⟹ (4 × 2) - 8

⟹ 8 – 8

⟹ 0

Since b^{2} – 4ac = 0 the roots are real and equal.

Now let us put the values in the above formula

x = 1/√2 , 1/√2

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