Answer :

2(x + 1)2 – 5(x + 1) = 12


= 2(x2 + 2x + 1) – 5x – 5 = 12


= 2x2 + 4x + 2 – 5x – 5 –12 = 0


= 2x2 – x – 15 = 0


= 2x2 – 6x + 5x – 15 = 0


= 2x (x – 3) + 5(x –3) = 0


= (2x + 5) (x – 3) = 0


2x + 5 = 0 or x – 3 =0


2x = –5 or x = 3


x = or x = 3


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