Q. 1 G4.0( 3 Votes )

Find the remainder using remainder theorem, when

x3 – ax2 – 5x + 2a is divided by x – a

Answer :

x3 – ax2 – 5x + 2a is divided by x – a

Remainder theorem states that if p(x) is any polynomial and a is any real number and If p(x) is divided by the linear polynomial (x – a) , then the remainder is p(a).

Let p(x) = x3 – ax2 – 5x + 2a and we have (x – a)

The zero of (x – a) is a

Now using Remainder theorem,

p(x) = x3 – ax2 – 5x + 2a is divided by x – a then, p(a) is the remainder

p(a) = (a)3 – a(a)2 – 5(a) + 2a

= a3 – a3 – 5a+ 2a

= – 3a

Remainder = –3a

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses