Answer :

x^{3} – ax^{2} – 5x + 2a is divided by x – a

Remainder theorem states that if p(x) is any polynomial and a is any real number and If p(x) is divided by the linear polynomial (x – a) , then the remainder is p(a).

Let p(x) = x^{3} – ax^{2} – 5x + 2a and we have (x – a)

The zero of (x – a) is a

Now using Remainder theorem,

p(x) = x^{3} – ax^{2} – 5x + 2a is divided by x – a then, p(a) is the remainder

p(a) = (a)^{3} – a(a)^{2} – 5(a) + 2a

= a^{3} – a^{3} – 5a+ 2a

= – 3a

Remainder = –3a

Rate this question :

Find the remaindeTamilnadu Board Math Term-I

If (x – 1) divideTamilnadu Board Math Term-I

Find the remaindeTamilnadu Board Math Term-I

Find the remaindeTamilnadu Board Math Term-I

If the polynomialTamilnadu Board Math Term-I

Find the value ofTamilnadu Board Math Term-I

Find the remaindeTamilnadu Board Math Term-I

Find the remaindeTamilnadu Board Math Term-I

When the polynomiTamilnadu Board Math Term-I

Find the remaindeTamilnadu Board Math Term-I