Q. 1 G4.0( 3 Votes )
Find the remainder using remainder theorem, when
x3 – ax2 – 5x + 2a is divided by x – a
Answer :
x3 – ax2 – 5x + 2a is divided by x – a
Remainder theorem states that if p(x) is any polynomial and a is any real number and If p(x) is divided by the linear polynomial (x – a) , then the remainder is p(a).
Let p(x) = x3 – ax2 – 5x + 2a and we have (x – a)
The zero of (x – a) is a
Now using Remainder theorem,
p(x) = x3 – ax2 – 5x + 2a is divided by x – a then, p(a) is the remainder
p(a) = (a)3 – a(a)2 – 5(a) + 2a
= a3 – a3 – 5a+ 2a
= – 3a
Remainder = –3a
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