Q. 1 G4.2( 5 Votes )

Solve the followi

Answer :

Now in the above quadratic equation the coefficient of x2 is 4. Let us make it unity by dividing the entire quadratic equation by 4.

4x2 + 4bx – (a2 – b2) = 0


x2 + bx = (a2 – b2)/4


Now by taking half of the coefficient of x and then squaring it and adding on both LHS and RHS sides.


Coefficient of x = b


Half of b = b/2


Squaring the half of b = b/4



Now the LHS term is a perfect square and can be expressed in the form of (a-b) 2 = a2 – 2ab + b2 where a = x and b = b/2




On simplifying both RHS and LHS we get an equation of following form,


(x ± A)2 = k2



Taking Square root of both sides.



Now taking the positive part,




x = (a – b) / 2


Now taking the negative part,




x = - (a + b) / 2


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