Q. 1 E5.0( 7 Votes )

# Solve the followi

Now in the above quadratic equation the coefficient of x2 is 2. Let us make it unity by dividing the entire quadratic equation by 2.

x2 + 1/2x - 2 = 0

x2 + 1/2 x = 2

Now by taking half of the coefficient of x and then squaring it and adding on both LHS and RHS sides.

Coefficient of x = 1/2

Half of 1/2 = 1/4

Squaring the half of 1/2 = 1/16 Now the LHS term is a perfect square and can be expressed in the form of (a-b) 2 = a2 – 2ab + b2 where a = x and b = 1/4 On simplifying both RHS and LHS we get an equation of following form,

(x ± A)2 = k2 Taking Square root of both sides. Now taking the positive part,   Now taking the negative part,   Rate this question :

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