Q. 1 C3.7( 3 Votes )

# Find the remainder using remainder theorem, when

2x^{3} – 4x^{2} + 7x + 6 is divided by x – 2

Answer :

2x^{3} – 4x^{2} + 7x + 6 is divided by x – 2

Remainder theorem states that if p(x) is any polynomial and a is any real number and If p(x) is divided by the linear polynomial (x – a) , then the remainder is p(a).

Let p(x) = 2x^{3} – 4x^{2} + 7x + 6 and we have (x – 2)

The zero of (x – 2) is 2

Now using Remainder theorem,

p(x) = 2x^{3} – 4x^{2} + 7x + 6 is divided by x – 2 then, p(2) is the remainder

p(2) = 2(2)^{3} – 4(2)^{2} + 7(2) + 6

= 16 – 16 + 14 +6

= 20

Remainder = 20

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