Q. 1 A4.2( 5 Votes )

Find the remainder using remainder theorem, when

3x3 + 4x2 – 5x + 8 is divided by x – 1

Answer :

3x3 + 4x2 – 5x + 8 is divided by x – 1


Remainder theorem states that if p(x) is any polynomial and a is any real number and If p(x) is divided by the linear polynomial (x – a) , then the remainder is p(a).


Let p(x) = 3x3 + 4x2 – 5x + 8 and we have (x – 1)


The zero of (x – 1) is 1


Now using Remainder theorem,


p(x) = 3x3 + 4x2 – 5x + 8 is divided by x – 1 then, p(1) is the remainder


p(1) = 3(1)3 + 4(1)2 – 5(1) + 8


= 3 + 4 – 5 + 8


= 10


Remainder = 10


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