# Using elementary

First of all we need to check whether the matrix is invertible or not. For that-

For the inverse of a matrix A to exist,

Determinant of A ≠ 0

Here A = (2)(-2) – (-6)(1) = 2

So the matrix is invertible.

Now to find the inverse of the matrix,

We know AA-1 = I

Let’s make augmented matrix-

[ A : I ]

Apply row operation- R2 R2 R1

Apply row operation- R1 R1/2

Apply row operation- R1 R1 + 3R2

The matrix so obtained is of the form –

[I : A-1]

Hence inverse of the given matrix-

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