Q. 4 C5.0( 1 Vote )

# The following tab

GIVEN: FORMULA USED:

Mean = Median = Mode = Maximum number of terms

Let weight of student be x

And number of student be frequency (f) For Mean:

Mean = ∑xf = 188 + 150 + 371 + 112 + 240

= 1061

∑f = 4 + 3 + 7 + 2 + 4

= 20

Mean = = 53.05

For Median

Total frequency (N) = ∑f = 20

N/2 = = 10

Which lies in commutative frequency 14

Which is having value of x to be 53

Median = 53

For Mode

Maximum number of terms(f) in above table is 7

7 terms are of value 53

Mode = 53

CONCLUSION: The data is having Mean to be 53.05

Mode to be 53

Median to be 53

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

The following tabTamilnadu - Math Term-3

The age of the emTamilnadu - Math Term-3

Find the mean, meTamilnadu - Math Term-3

The following tabTamilnadu - Math Term-3

Obtain the A.M ofTamilnadu - Math Term-3

For a month, a faTamilnadu - Math Term-3

The following datTamilnadu - Math Term-3

The average heighTamilnadu - Math Term-3

Find the WeightedTamilnadu - Math Term-3

If the average ofTamilnadu - Math Term-3