Q. 2 K5.0( 3 Votes )

# Solve the following equations by factorization method:

abx^{2} + (b^{2} – ac)x – bc = 0

Answer :

On factorizing the above equation,

abx^{2} + (b^{2} – ac)x – bc = 0

abx^{2} + b^{2}x – acx – bc = 0

bx(ax + b) – c(ax + b) = 0

(bx – c) (ax + b) = 0

Solving the first part,

bx – c = 0

bx = c

x = c/b

Solving the second part,

ax + b = 0

ax = -b

x = -b / a

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