Q. 2 I4.3( 3 Votes )

Solve the followi

Answer :

Cross Multiplying in the above equation,

(x + 3) × (2x – 3) = (3x – 7) × (x + 2)


2x2 – 3x + 6x – 9 = 3x2 + 6x – 7x – 14


2x2 + 3x – 9 = 3x2 – x – 14


3x2 – 2x2 – x - 3x – 14 + 9 = 0


x2 - 4x – 5 = 0


On factorizing the above equation,


x2 + x – 5x – 5 = 0


x(x + 1) – 5(x + 1) = 0


(x – 5) (x + 1) = 0


Solving the first part,


x – 5 = 0


x = 5


Solving the second part,


x + 1 = 0


x = -1


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