Q. 2 H5.0( 1 Vote )

# Solve the following equations by factorization method:

x^{2} + 8x + 7

Answer :

On factorizing the above equation,

x^{2} + 8x + 7 = 0

x^{2} + 7x + x + 7 = 0

x(x + 7) + 1(x + 7) = 0

(x + 7) (x + 1) = 0

Solving the first part,

x + 7= 0

x = -7

Solving the second part,

x + 1 = 0

x = -1

Rate this question :

If u(x) = (x – 1)^{2} and v(x) = (x^{2} – 1) the check the true of the relation LCM × HCF = u(x) × v(x).

Find the lowest common multiple of the following expressions:

24x^{2}yz and 27x^{4}y^{2}z^{2}

Rajasthan Board Mathematics

Solve the following quadratic equations by using Shridharacharya Quadratic Formula:

p^{2}x^{2} + (p^{2} – q^{2})x – q^{2} = 0

Rajasthan Board Mathematics

Solve the following equation by factorization method:

Rajasthan Board Mathematics

The area of a rectangular plot is 528 m^{2}. The length of the plot (in m) is 1 more than double of breadth. Representing by the required quadratic equation find the length and breadth of the plot.

The LCM and HCF of two quadratic expressions are respectively x^{3} – 7x + 6 and (x – 1). Find the expressions.

If α and β are the zeroes of the quadratic polynomial f(x) = x^{2} – px + q then find the values of the following:

(i) α^{2} + β^{2} (ii)

Rajasthan Board Mathematics

Find the zeroes of the quadratic polynomial 2x^{2} – 8x + 6 and examine the truth of the relationship between the zeroes and the coefficients.

Write Shridharacharya Formula of finding the roots of the quadratic equation ax^{2} + bx + c = 0.

Solve the following equation by factorization method:

Rajasthan Board Mathematics