Q. 24.4( 19 Votes )
For which value (
Answer :
The given pair of linear equations is
kx + 3y = k - 3 …(i)
and 12x + ky = k …(ii)
On comparing with ax + by = c = 0, we get
a1 = , b1 = 3, c1 = -(k - 3)
And a2 = 12, b2 = , c2 = - k
a1 /a2 =
/12
b1 /b2 = 3/
c1 /c2 =
For no solution of the pair of linear equations,
a1/a2 = b1/b2 c1/c2
So =
Taking first two parts, we get
/12 = 3/
k2 = 36
k = 6
Taking last two parts, we get
3k k(k - 3)
k2 - 6k 0
so, k 0,6
Hence, required value of k for which the given pair of linear equations has no solution is k = - 6.
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Introduction to Linear Equations in Two Variables62 mins
Revision on Substitution and Elimination Method44 mins
Revision on Word Problems - 150 mins
Revision on Word Problems - 235 mins
Two Stories about Flying39 mins
Human Reproduction in One Shot45 mins
All 3 marks Numericals46 mins
All 4 marks Numericals43 mins
Reflection of light-238 mins
All Diagram Questions45 mins




















Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
Solve the followi
KC Sinha - MathematicsSolve each of the
RS Aggarwal - MathematicsIf 2x – 3y = 7 an
RD Sharma - MathematicsA plane left 30 m
KC Sinha - MathematicsA boat goes 16 km
KC Sinha - Mathematics