Q. 2

# Find the value of x in the diagram below.

We know by proposition 1,

DAB + BAC = 180°

130° + BAC = 180°

BAC = 180° - 130°

BAC = 50°

And again We know by proposition 1,

BCE + BCA = 180°

90° + BCA = 180°

BCA = 180° - 90°

BCA = 90°

In triangle ABC,

ACB + BAC + CBA = 180°

90° + 50° + CBA = 180°

CBA = 180° - 140°

CBA = 40°

BFG = x = CBA = 40° (alteranate angles)

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