(4x3 – 2x2 + 6x + 7) ÷ (3 + 2x)
We see that the equation is not arranged in descending order, so we need first arrange it in descending order of the power of x.
Therefore it becomes,
(4x3 – 2x2 + 6x + 7) ÷ (2x + 3)
Now we need to divide (4x3 – 2x2 + 6x + 7) by (2x + 3)
Now we need to find out by how much should we multiple “x” to get a value as much as 4x3.
To get x3, we need to multiply x×x2.
Therefore we need to multiply with 2x2 × (2x + 3) and we get (4x3 + 6x2) now subtract (4x3 + 6x2) from 4x3 – 2x2 + 6x + 7so we get – 8x2.
Now we carry 6x + 7along with 4x2, as shown below
So, in same way we have keep dividing till we get rid of x as shown below.
here (2x + 3) × (–4x)
= – 8x2 – 12x
here (2x + 3) × 9
= 18x + 27
Therefore, we got the quotient = 2x2 – 4x + 9 and
Remainder = –20
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