Q. 1 D5.0( 2 Votes )

# Find the quotient

(4x3 – 2x2 + 6x + 7) ÷ (3 + 2x)

We see that the equation is not arranged in descending order, so we need first arrange it in descending order of the power of x.

Therefore it becomes,

(4x3 – 2x2 + 6x + 7) ÷ (2x + 3)

Now we need to divide (4x3 – 2x2 + 6x + 7) by (2x + 3)

Now we need to find out by how much should we multiple “x” to get a value as much as 4x3.

To get x3, we need to multiply x×x2.

Therefore we need to multiply with 2x2 × (2x + 3) and we get (4x3 + 6x2) now subtract (4x3 + 6x2) from 4x3 – 2x2 + 6x + 7so we get – 8x2.

Now we carry 6x + 7along with 4x2, as shown below

So, in same way we have keep dividing till we get rid of x as shown below. here (2x + 3) × (–4x)

= – 8x2 – 12x

here (2x + 3) × 9

= 18x + 27

Therefore, we got the quotient = 2x2 – 4x + 9 and

Remainder = –20

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