Q. 1 C5.0( 2 Votes )

Check whether the

Answer :

Let us solve the above equation,

x3 + 3x + 1 = (x – 2)2


x3 + 3x + 1 = x2 – 2 × 2 × x + 4 …….. [(a-b) 2 = a2 – 2ab + b2]


x3 + 3x + 1 = x2 – 4x + 4


x3 + 3x + 1 - x2 + 4x - 4 = 0


x3 - x2 + 7x - 3 = 0


Since on solving the equation we do get the third power of x along with second power which proves that the following set of equation is not quadratic. A quadratic equation contain the highest power of x which is 2.


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