Q. 1 C5.0( 2 Votes )

Find the quotient the and remainder of the following division.

(9 + 4x + 5x2 + 3x3) ÷ (x+ 1)

Answer :

(9 + 4x + 5x2 + 3x3) ÷ (x + 1)


We see that the equation is not arranged in descending order, so we need first arrange it in descending order of the power of x.


Therefore it becomes,


(3x3 + 5x2 + 4x + 9) ÷ (x + 1)


Now we need to divide (3x3 + 5x2 + 4x + 9) by (x + 1).


Now we need to find out by how much should we multiple “x” to get a value as much as 3x3.


To get x3, we need to multiply x×x2.


Therefore, we need to multiply with 3x2 × (x + 1) and we get (3x3 + 3x2) now subtract (3x3 + 3x2) from 3x3 + 5x2 + 4x + 9 so we get 2x2.


Now we carry 4x + 9 along with 2x2, as shown below


So, in same way we have keep dividing till we get rid of x as shown below.



here (x + 1) × ( 2x)


= 2x2 + 2x


here (x + 1) × 2


= 2x + 2


Therefore, we got the quotient = 3x2 + 2x + 2 and


Remainder = 7


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