Q. 1 B5.0( 2 Votes )

Find the quotient the and remainder of the following division.

(2x2 – 3x – 14) ÷ (x + 2)

Answer :

(2x2 – 3x – 14) ÷ (x + 2)


We see that the equation is already arranged in descending order.


Now we need to divide (2x2 – 3x – 14) by (x + 2).


Now we need to find out by how much should we multiple “x” to get a value as much as 2x2.


To get x2, we need to multiply x×x.


Therefore, we need to multiply with 2x × (x + 2) and we get (2x2 + 4x) now subtract (2x2 + 4x) from 2x2 – 3x – 14 so we get –7x.


Now we carry 14 along with –7x, as shown below


So, in same way we have keep dividing till we get rid of x as shown below.



here (x + 2) × (– 7)


= – 7x – 14


Therefore, we got the quotient = 2x – 7 and


Remainder = 0


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