Q. 1 A4.6( 5 Votes )

# Find the zeros of the following quadratic polynomials and verify the basic relationships between the zeros and the coefficients.x2 – 2x – 8

Let f(x) = x2 – 2x – 8

To find out zeros of the given polynomial.

We put f(x) = 0

x2 – 2x – 8 = 0

To find out roots of this polynomial we use splitting of middle term method.

According to this method we need to find two numbers whose sum is – 2 and product is 8.

x2 – (4 – 2)x – 8 = 0

x2 – 4x + 2x – 8 = 0

x(x – 4) + 2(x – 4) = 0

(x + 2)(x – 4) = 0

x = – 2 and x = 4.

Our zeros are α = – 2 and β = 4.

sum of zeros = α + β = – 2 + 4 = 2.

Product of zeros = αβ = ( – 2) × 4 = – 8.

Comparing f(x) = x2 – 2x – 8 with standard equation ax2 + bx + c = 0.

We get, a = 1, b = – 2 and c = – 8

We can verify,

Sum of zeros = i.e. α + β = α + β = 2

Product of zeros = αβ = αβ = – 8.

Hence, relationship between zeros and coefficient is verified.

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