Q. 1 A5.0( 2 Votes )

# Find the quotient

(5x3 – 8x2 + 5x – 7) ÷ (x – 1)

We see that the equation is already arranged in descending order.

Now we need to divide (5x3 – 8x2 + 5x – 7) by (x – 1).

Now we need to find out by how much should we multiple “x” to get a value as much as 5x3.

To get x3, we need to multiply x×x2.

Therefore, we need to multiply with 5x2 × (x – 1) and we get (5x3 – 5x2) now subtract (5x3 – 5x2) from 5x3 – 8x2 + 5x – 7 so we get – 3x2.

Now we carry 5x – 7 along with – 3x2, as shown below

So, in same way we have keep dividing till we get rid of x as shown below. here (x – 1) × (– 3x)

= – 3x2 + 3x

here (x – 1) × 2

= 2x – 2

Therefore, we got the quotient = 5x2 – 3x + 2 and

Remainder = –5

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