Answer :

(5x^{3} – 8x^{2} + 5x – 7) ÷ (x – 1)

We see that the equation is already arranged in descending order.

Now we need to divide (5x^{3} – 8x^{2} + 5x – 7) by (x – 1).

Now we need to find out by how much should we multiple “x” to get a value as much as 5x^{3}.

To get x^{3}, we need to multiply x×x^{2}.

Therefore, we need to multiply with 5x^{2} × (x – 1) and we get (5x^{3} – 5x^{2}) now subtract (5x^{3} – 5x^{2}) from 5x^{3} – 8x^{2} + 5x – 7 so we get – 3x^{2}.

Now we carry 5x – 7 along with – 3x^{2}, as shown below

So, in same way we have keep dividing till we get rid of x as shown below.

here (x – 1) × (– 3x)

= – 3x^{2} + 3x

here (x – 1) × 2

= 2x – 2

Therefore, we got the quotient = 5x^{2} – 3x + 2 and

Remainder = –5

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Find the quotientTamilnadu Board Math Term-I

Find the quotientTamilnadu Board Math Term-I

Find the quotientTamilnadu Board Math Term-I

Find the quotientTamilnadu Board Math Term-I

Find the quotientTamilnadu Board Math Term-I