Q. 1 A5.0( 2 Votes )

Find the quotient the and remainder of the following division.

(5x3 – 8x2 + 5x – 7) ÷ (x – 1)

Answer :

(5x3 – 8x2 + 5x – 7) ÷ (x – 1)

We see that the equation is already arranged in descending order.


Now we need to divide (5x3 – 8x2 + 5x – 7) by (x – 1).


Now we need to find out by how much should we multiple “x” to get a value as much as 5x3.


To get x3, we need to multiply x×x2.


Therefore, we need to multiply with 5x2 × (x – 1) and we get (5x3 – 5x2) now subtract (5x3 – 5x2) from 5x3 – 8x2 + 5x – 7 so we get – 3x2.


Now we carry 5x – 7 along with – 3x2, as shown below


So, in same way we have keep dividing till we get rid of x as shown below.



here (x – 1) × (– 3x)


= – 3x2 + 3x


here (x – 1) × 2


= 2x – 2


Therefore, we got the quotient = 5x2 – 3x + 2 and


Remainder = –5


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses