Q. 4 A5.0( 1 Vote )

Check the commuta

Answer :

Given that * is a binary operation on Z defined by a*b = a + b + ab for all a,bZ.


We know that commutative property is p*q = q*p, where * is a binary operation.


Let’s check the commutativity of given binary operation:


a*b = a + b + ab


b*a = b + a + ba


b*a = a + b + ab


b*a = a*b


Commutative property holds for given binary operation * on Z.


We know that associative property is (p*q)*r = p*(q*r)


Let’s check the associativity of given binary operation:


(a*b)*c = (a + b + ab)*c


(a*b)*c = (a + b + ab + c + ((a + b + ab)×c))


(a*b)*c = a + b + c + ab + ac + ac + abc ...... (1)


a*(b*c) = a*(b + c + bc)


a*(b*c) = (a + b + c + bc + (a×(b + c + bc)))


a*(b*c) = a + b + c + ab + bc + ac + abc ...... (2)


From (1) and (2) we can clearly say that associativity holds for the binary operation ‘*’ on ‘Z’.


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