Answer :

Theorem 1: Sum of all the angles of triangles is 180°


Let PQR be y


In Δ SQR,


SQ = SR


SQR = SRQ


SQR + SRQ + QSR = 180° (Angle Sum Property)


2 SQR + 70° = 180°


2 SQR = 180° - 70°


2 SQR = 110°



SQR = 55° = SRQ


In Δ PQR,


PQR + PRQ + RPQ = 180°


y + y + 40° = 180°


2y + 40° = 180°


2y = 180° - 40°


2y = 140°



y = 70°


PQR = PQS + SQR


70° = x° + 55°


x° = 70° - 55°


x° = 15°


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