Answer :
Theorem 1: Sum of all the angles of triangles is 180°
Let ∠ PQR be y
In Δ SQR,
SQ = SR
∴ ∠ SQR = ∠ SRQ
∠ SQR + ∠ SRQ + ∠ QSR = 180° (Angle Sum Property)
⇒ 2 ∠ SQR + 70° = 180°
⇒ 2 ∠ SQR = 180° - 70°
⇒ 2 ∠ SQR = 110°
⇒ 
⇒ ∠ SQR = 55° = ∠ SRQ
In Δ PQR,
∠ PQR + ∠ PRQ + ∠ RPQ = 180°
⇒ y + y + 40° = 180°
⇒ 2y + 40° = 180°
⇒ 2y = 180° - 40°
⇒ 2y = 140°
⇒ 
⇒ y = 70°
∠ PQR = ∠ PQS + ∠ SQR
⇒ 70° = x° + 55°
⇒ x° = 70° - 55°
⇒ x° = 15°
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